solve the system of equation 2x+y=1, y=2x^2+3x+1

Answer 1

y = 1 - 2x

1 - 2x = 2x² + 3x + 1

2x² + 5x - 2 = 0

Using the quadratic formula with a=2, b = 5, c=-2, gives x = (-5 ±√41)/4

and then you can just find y by substituting x back into the first equation