8y^2-4y-60
4(2y^2 -y-15). Now factor by grouping (YOU NEED TO KNOW HOW TO DO THIS)
4(2y^2 -6y +5y 15)
4( 2y(y-3) +5(y-3)
4(2y+5)(y-3) this is the complete factorization but it does not contain any of the terms you are asked to choose from so I will manipulate this to
2(2y+5)(2)(y-3) which give me 4y+10 and 2y-6 which are among your choices