Identify the zeros of the function f(x) = 2x2 − 2x + 13 using the quadratic formula.

Answer 1

ax²+bx+c = 0

x = (-b±√(b²-4ac))/(2a) = (2±√(4-4(2)13))/(2•2)

= (2±√(-100))/4 = 2/4 ±(10/4)i = 1/2 ± (5/2)i = 1/2 + 5i/2, 1/2-5i/2

Answer 2

The quadratic formula is as follows:

x = [-b +/- √(b² - 4ac)] / 2a

where x represents the zeros.

The general form of a quadratic function is: f(x) = ax² + bx + c, where a, b, and c are real numbers.

In the equation you've listed above, the a-value is 2, the b-value is -2, and the c-value is 13. If we input these values into their appropriate spots into the quadratic formula then it should look like:

x = -(-2) +/- √((-2)² - 4(2)(13))] / 2(2)

which gives us out the values: x = 1/2 +/- 5i/2

Answer 3

A=2, B=-2, C=13

b^2 - 4ac = (-2)^2 - 4(2)(13)

= 4 - 8*13

= 4 - 104

= -100

sqrt(-100) = 10i

x = [2 +or- 10i]/4 = [1 +or- 5i]/2

CHECK:

x^2 = [1 + 5i][1 + 5i]/4 = [ 1 + 10i + -25]/4

= [ 10i - 24]/4

= [5i -12]/2

2x^2 -2x =

[5i -12] - (1 + 5i) = -13

which shows the answer is correct

ANSWER:

x = [1 +or- 5i]/2