find the first five terms of the arithmetic sequence.

Question

If t₆= 16 and t₁₁= 81, find the first five terms of the arithmetic sequence.

Answer 1

tn = (n-2) ^ 2

then t6 = (6-2) ^2 = 4^2 = 16

and t11 = (11 - 2) ^ 2 = 9^ 2 = 81

Similarly,

t1 = (1-2) ^2 = 1

t2 = (2-2) ^2 = 0

t3 = (3-2) ^2 = 1

t4 = (4-2) ^2 = 4

t5 = (5-2) ^2 = 9