dentify the​ vertex, the axis of​ symmetry, the maximum or minimum​ value, and the range of the parabola.

Question

y=x2+6x+10

Answer 1

For parabola equation in form y = ax^2 + bx + c

For x^2 + 6x + 10

a = 1 b = 6 and c = 10

Since a = 1 > 0, parabola will open upwards

axis of symmetry = x = -b/2a = -6/2 = -3 ---> x = -3

plug in x = -3, y = (-3)^2 + 6(-3) + 10 = 1, so vertex is (-3, 1)

since a > 1, vertex is minimum point

since the vertex is at (-3,1) the range is (1,infinity)