the height in feet of an object t after being launched from the ground can be modeled by the function h(t) =-16t(t-5) what is the height of the object after 1 second?

Answer 1

Hi Millena,

Here you would just plug 1 second into the equation. The equation will give you the height of the object after t seconds.

t = 1 second

h(t) = - 16(t)(t-5)

h(t) = -16(1)(1-5)

h(t) = -16(-4) = 64

The object is 64 feet in the air after 1 second