We can do this two ways.
1. y = mx + b
2 = -5(1) + b
2 = -5 + b
b = 7
y = -5x + 7
2. y - y1 = m(x - x1)
y - 2 = -5(x - 1)
y - 2 = -5x + 5
y = -5x + 7
Aliyah S.
asked 01/13/21Write an equation of the line that passes through (1,2) and is parallel to the line y=-5x+4
We can do this two ways.
1. y = mx + b
2 = -5(1) + b
2 = -5 + b
b = 7
y = -5x + 7
2. y - y1 = m(x - x1)
y - 2 = -5(x - 1)
y - 2 = -5x + 5
y = -5x + 7
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