It's a math question but I couldn't fit the full thing up here.

Question

sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 11 people took the trip. She was able to purchase coach tickets for $220 and first class tickets for $1180. She used her total budget for airfare for the trip, which was $9140. How many first class tickets did she buy? How many coach tickets did she buy? I couldn't fit the full question up there.

Answer 1

C=# of coach tickets

F=#of First Class tickets

C + F = 11

220C + 1180F = 9140

I always find elimination is easier than substitution...

Multiply the first equation by 11 & divide the 2nd equation by 20

11C + 11F = 121

11C + 59F = 452

Subtract: 48F=336 => F=7

You should be able to get it from here.

Answer 2

The 2 equations you need are stated below.

1. 220x + 1180y = 9140
2. (x people in coach times 220 dollars plus y people in first class times 1180 dollars equals a total of 9140)
3. x + y = 11
4. x people in coach plus y people in first class equal 11 total people

Use one equation to solve for the other, plug it back in to verify

x = 11 - y

220(11-y) + 1180y = 9140

2420 - 220y + 1180y = 9140

2420 +960y = 9140

960y = 6720

y = 6720/960 = 7

x + y = 11

x + 7 = 11

x = 4

7 people were in first class

4 people were in coach

Plug x = 4 and y = 7 back into both of your starting equations and verify that they are equal (they are)