
Patrick B. answered 01/06/21
Math and computer tutor/teacher
A=1, as it should
B = -6
x^2 - 6x - 5 = 0
x^2 - 6x = 5
(B/2)^2 = (-6/2)^2 = (-3)^2 = 9
x^2 - 6x + 9 = 5+9
(x - 3)(x - 3) = 14
(x - 3)^2 = 14
x - 3 = +or- sqrt(14)
x = 3 +or- sqrt(14)
check:
x = 3 + sqrt(14)
x^2 = x*x = (3 + sqrt(14))(3 + sqrt(14))
= 9 + 6*sqrt(14) + 14
= 23 + 6 *sqrt(14)
x^2 - 6x - 5 =
23 + 6 * sqrt(13) - 6( 3 + sqrt(14)) - 5 =
23 + 6 * sqrt(13) - 18 - 6*sqrt(14) - 5 =
23 - 18 - 5 =
5-5=
0