Raymond B. answered • 12/22/20
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5
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Math, microeconomics or criminal justice
L=25 + W
2L+2W = 150
2(25+W) + 2W = 150
50 +2W + 2W = 150
4W= 100
W = 25 meters
L =50 meters
Chris J.
asked • 12/22/20The perimeter of a rectangle is 150 meters. If the length of the rectangle is 25 meters more than the width, what are the dimensions of the rectangle?
The perimeter of a rectangle is 150 meters. If the length of the rectangle is 25 meters more than the width, what are the dimensions of the rectangle?
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Kathy G. answered • 12/22/20
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Excellent Math Tutor for JR/SR High and successful SAT/ACT Tutor
Let w = width and l = length = w + 25
The perimeter would be w + w + 25 +w + w +25 = 150
This gives 4w + 50 = 150
Solve for w to get w = 25
Then l = 50
The dimensions are 25 x 50
Chris J.
Hi Kathy, would you happen to know this question I am stumped on? A worker invested $26,000 into two accounts, one yielding 5% interest and the other yielding 12%. If he recieved a total of $1720 at the end of the year, how much did he invest at 5% ?
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12/22/20
Kathy G.
Let x = the amount deposited in the account with 5% interest. Then the amount deposited in the account with 12% would be 26000 - x (because he deposited 26000 total between the 2 accounts). Now you can set up the equation .05x + .12(26000 - x) = 1720 Solving this gives -.07x + 3120 = 1720 -.07x = -1400 x = 20000 which = the amount invested at 5%
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12/22/20
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Chris J.
Hi Raymond, would you happen to know this question I am stumped on? A worker invested $26,000 into two accounts, one yielding 5% interest and the other yielding 12%. If he recieved a total of $1720 at the end of the year, how much did he invest at 5% ?12/22/20