Kai C.
asked • 12/16/20f(x)= x^5+2x^4+18x^3+36x^2-19x-38
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1 Expert Answer
f(x)= x^5+2x^4+18x^3+36x^2-19x-38
factors to the following:
f(x) = x^4(x+2)+18x^2(x+2)-19(x+2)
f(x) = (x^4+18x^2-19)(x+2)
f(x) = (x^2+19)(x^2-1)(x+2)
f(x) = (x^2+19)(x+1)(x-1)(x+2)
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Mark M.
What is your question?12/17/20