Algebra II Question

Question

y varies directly as x and inversely as the square of z. y=32 when x=36 and z=3.

Find y when x=3

and

z=6.

Answer:?

Answer 1

y=kx/z²

32 = 36k/9 => k=8

y = 8*3/36

I will leave it to you to evaluate this fraction.