X^3 +2x^2-7x=0
x(x^2+2x+7)=0 One solution is x=0 the other is (x^2+2x+7) = 0 This does not factor so need to use the quadratic formula to solve
this is [ -2+/-sqroot (4-28)/2 = (-2+Sqroot-24)/2 and (-2 -sqroot-24)/2 these can be simplified to
( -2 +2sqroot-6)/2 = -1+ sqroot-6
(-2 -2sqroot-6)/2 = -1 -sqroot-6
so a=-1, b=1, c=-6
Stephen K.
12/14/20
Chloe B.
Thank you so much for your help!12/14/20