The cost of two toy cars and a toy bus is $47. Four times the cost of the toy bus is 28 more than eight times the cost of the toy car. Find the cost of a toy car. $10 $17 $20 $27

Answer 1

Since 2 cars + 1 bus = $47

and 4(bus) = 28 + 8(cars) * divide by 4*

1 bus = 7 + 2(cars)

Plug in new equation for 1 bus in original:

2 cars + 1 bus = $47

2(cars) + (7 + 2(cars)) = $47

4(cars) + 7 = $47 *subtract 7

4(cars) = $40 *divide by 4

The cost of one car is $10

Answer 2

2c + b = 47

4b = 8c + 28

Fitst, let's solve the first equation for b by subtracting 2c from both sides.

b = 47 - 2c

Now, substitute 47 - 2c for b in the 2nd equation.

4(47 - 2c) = 8c + 28

Solve for c for your answer.

Answer 3

2c+b=47

4b=8c+28

b=2c+7

2c+(2c+7)=47

4c+7=47

4c=40

c=10

b=27

The cost of a toy car is $10.