Can someone help me with a math problem?

Question

Find the 30th term of an arithmetic sequence with the first term of 40 and a common difference of -6

Answer 1

a30 = a1 +(-6)(30-1) = 40-6(29) = 40-174 =- 134 = the 30th term of the arithmetic sequence if 1st term = 40 = a1, and common difference = -6=d

an = a1 +d(n-1) is the general formula for the nth term