
Mark M. answered 12/02/20
Mathematics Teacher - NCLB Highly Qualified
w1f1 = w2f2
(250)(900) = w2(600)
Can you solve for w2 and answer?
Scott S.
asked 12/02/20The frequency of an electromagnetic wave varies indirectly as its wavelength. A wavelength of 250 meters has a frequency of 900 kilocycles per second. What is the wavelength if the frequency is 600 kilocycles per second?
Mark M. answered 12/02/20
Mathematics Teacher - NCLB Highly Qualified
w1f1 = w2f2
(250)(900) = w2(600)
Can you solve for w2 and answer?
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