Find the equation of the line in standard form that passes through the following points. Eliminate any fractions and simplify your answer. (2,−10) and (7,−11)

Answer 1

M = (-11 - -10)/ (7-2)

= (-11 + 10)/ (7-2)

= -1/5

B = y - mx = -10 - (-1/5)(2)

= -10 + 2/5

= -50/5 + 2/5

= -48/5

and

B = -11 - (-1/5)(7)

= -11 + 7/5

= -55/5 + 7/5

= -48/5

y = (-1/5)x - 48/5

5y = -x - 48

x + 5y = -48

Note that when x=2 --> 2 + 5y=-48

5y = -50

y = -10, so (2,-10)

and when x = 7 --> 7 + 5y = -48

5y = -55

y = -11

so (7,-11)

x + 5y = -48