Algebra 2 question

Question

The sum of three numbers is 86. The third number is 4 times the second. The second number is 10 more than the first. What are the numbers?

Answer 1

A+B+C = 86

C=4B

B=10+A or A=B-10

B-10 + B + 4B = 86

6B = 96

B = 96/6 = 16

C = 4(16) = 64

A=16-10 = 6

the 3 numbers are 6, 16 and 64