G(x)=2f(x)+5. A third function h(x)=x^2-3 is defined by the formula below. What is the value of g(h(2))? Show how you arrived at your answer.

Answer 1

We have to find g(h(2))

So we first find h(2)

Now h(2) = x² - 3 where put x= 2

So we get h(2)= 1

Thus we now have to find g(1)

Similar to above to find g(1)

Put x=1 in g(x)

Therefore, g(1) = 2*f(1)+5

Now just put the value for f(1) if given or submit the above answer.

Answer 2

The f(x) in the middle of g(x) doesn't make sense. It isn't defined in the problem anywhere. I assume this is x instead.

Always start with the inside and work your way out.

h(2) = (2)²-3 = 1 Take this answer and plug it into g(x)

g(1) = 2(1)+5

7

Answer 3

to do this we need to find h(2) and then plug that into G(x):

h(2)=2²-3=4-3=1

Now plug 1 into G(x):

G(1)=2f(1)+5

That's the answer unless there is an f(x) equation you didn't state above.