Suppose that f(x)=-3x^3-11x^2-8x+4 If (x + 2) is a factor of f(x), what is f(x) completely factored?

Answer 1

(x+2)(x+2)(1-3x) or (1-3x)(x+2)^2

divide x+2 into the cubic function, using either long or synthetic division to get -3x^2-5x+2. That trinomial factors into x+2 and 1-3x. Just use trial and error to factor. But notice the -5 is one less than the 2 times -3