Yefim S. answered 11/18/20
Math Tutor with Experience
abs(x - a) > b;
x - a > b or x - a < - b
x > a + b or x < a - b
a + b = 7
a - b = - 5
a = 1, b = 6
abs(x - 1) > 6
Yefim S. answered 11/18/20
Math Tutor with Experience
abs(x - a) > b;
x - a > b or x - a < - b
x > a + b or x < a - b
a + b = 7
a - b = - 5
a = 1, b = 6
abs(x - 1) > 6
John C. answered 11/18/20
The Problem Solver
The absolute value function is symmetric around 0, so I'd look for an average.
Here we have 7 and -5, and the average is 1: 1 + 6 = 7, 1 - 6 = -5.
So |x - 1| > 6 when x > 7 or x < -5, as required.
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