Tom K. answered 11/12/20
Knowledgeable and Friendly Math and Statistics Tutor
Let the speed of the second truck be s
Then, the speed of the first truck is 12mph faster, or s + 12
As rt = d (rate times time equals distance), or t = d/r, and it is 780 miles
the time for the second truck is 780/s and the time for the first truck is 780/(s + 12)
The first truck arrive 4 hours earlier, so the second truck takes 4 more hours.
780/s - 780/(s+12) = 4
Multiplying through by s(s+12),
780(s+12) - 780 s = 4(s)(s+12)
780s + 780 * 12 - 780s = 4s^2 + 48s
4s^2 + 48s - 9360 = 0
s^2 + 12s - 2340 = 0
(s + 6 - 6√66)(s + 6 + 6√66 ) = 0 We only take the positive value of s.
The speed of the second truck is - 6 + 6√66
he speed of the first truck is 6 + 6√66