Help please!? Consider the function 𝑓(𝑥) = 𝑟𝑜𝑢𝑛𝑑(𝑥), which rounds the input, x, to the nearest integer. Is this function one-to-one?

Answer 1

Hi Maria,

To answer, you need to know the definition of one-to-one. One-to-one functions hold the rule that each input has only one output (definition of a function) AND Each Output has only one input. The reason that the rounding function is NOT One-to-One is because there are more than one value (input) you can round to the same number (output).

I hope that clears up your question!

Bill

Answer 2

The function is not one to one since

round(0.25)=0

round(0.34)=0