the sides of a right triangle are consecutive integers, the area is 6. find the perimeter of the shape

Answer 1

legs of triangle

x

x+1

hypotenuse (always the longest side of a right triangle)

x+2

area of triangle = 1/2 * base * height (where base and height are two legs)

1/2(x)(x+1) = 6

(x)(x+1) = 12

x^2 + x = 12

x^2 +x - 12 = 0

(x+4)(x-3) = 0

x = -4 or 3

x can only equal 3

other leg = 4

hypotenuse = 5

perimeter = 12