Inactive Tutor answered 11/10/20
given function is f(x) = 4x + 20
let y = 4x + 20
rearrange (to make x subject) to get y - 20 = 4x => x = (y - 20) / 4
swap x and y naming so y = (x - 20) / 4
and inverse notation f-1(x) = (x - 20) / 4
Inactive Tutor answered 11/10/20
given function is f(x) = 4x + 20
let y = 4x + 20
rearrange (to make x subject) to get y - 20 = 4x => x = (y - 20) / 4
swap x and y naming so y = (x - 20) / 4
and inverse notation f-1(x) = (x - 20) / 4
To find the inverse function you do the following: y=4x+20 or 4x=y-20 or x=(1/4)y-5. Therefore, the inverse function is given by the formula f^{-1}(x)=(1/4)x-5.
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