This can be viewed as a linear difference equation: Δf(n) = -5.
The general solution is f(n) = -5n + C where C is an arbitrary constant.
Since f(1) = -20 = -5 + C, C=-15 and the general solution is f(n) = -15 - 5n and
f(10) = -65.
Alternatively you could write out the sequence: -20, -25, -30,....and eventually get to -65.
Or you could get to the arithmetic sequence by observing that f(1) = -20 and the difference is -5, which gets you the same result.