a sequence is defined by f(0)=−20 , f(n)= -20, f(n)= f(n-1)-5 for n1. explain why f(3)=−20−5−5−5

Question

a sequence is defined by f(0)=−20 , f(n)= -20, f(n)= f(n-1)-5 for n>1. explain why f(3)=−20−5−5−5

Mark M. · Accepted Answer

f(0) = -20f(1) = f(0) - 5 → f(1) = -20 - 5f(2) = f(1) - 5 → f(2) = -20 - 5 - 5f(3) = f(2) - 5 → f(3) = -20 - 5 - 5 - 5QED

a sequence is defined by f(0)=−20 , f(n)= -20, f(n)= f(n-1)-5 for n>1. explain why f(3)=−20−5−5−5