Brianna R.
asked 11/03/20PLEASE ANSWER FAST!!!
Find the zeros of h(x)=-2x^2-50
x=
x=
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1 Expert Answer
2x^2 - 50 = 0
2(x^2-25) = 0
(x+5)(x-5) = 0
zeros are -5 and 5
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Jacob F.
To find the zeros of a function, set that function equal to zero. So we get, h(x) = -2x^2 - 50 = 0. Add 50 to both sides of the equation then divide by -2, and then finally take the square root (don't forget about plus and minus sign with the square root). Good luck!11/03/20