start with vertex form
y = -3(x-5)^2
now expand
y= -3(x^2-10x+25)
y= -3x^2 +30x-75
Emma R.
asked 11/02/20what is a quadratic function in standard form that has vertex at (5, 0) and a vertical stretch of -3?
(it’s a homework question I’m stuck on)
start with vertex form
y = -3(x-5)^2
now expand
y= -3(x^2-10x+25)
y= -3x^2 +30x-75
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