Inactive Tutor answered 11/01/20
x4 + 125x = x(x3 + 125) = x(x + 5)(x2 - 5x + 25)
x4 + 5x3 + 4x2 + 20x = x(x3 + 5x2 + 4x + 20) = x(x + 5)(x2 + 4)
x4 - x3 -2x2 + 2x = x(x3 - x2 -2x + 2) = x(x - 1)(x2 -2)
x4 - 8x = x(x3 - 8) = x(x - 2)(x2 + 2x + 4)
Ashton F.
asked 10/31/201) f (x) = x 4 + 125x 2) f (x) = x 4 + 5x 3 + 4x 2 + 20x
3) f (x) = x 4 - x 3 - 2x 2 + 2x 4) f (x) = x 4 - 8x
Inactive Tutor answered 11/01/20
x4 + 125x = x(x3 + 125) = x(x + 5)(x2 - 5x + 25)
x4 + 5x3 + 4x2 + 20x = x(x3 + 5x2 + 4x + 20) = x(x + 5)(x2 + 4)
x4 - x3 -2x2 + 2x = x(x3 - x2 -2x + 2) = x(x - 1)(x2 -2)
x4 - 8x = x(x3 - 8) = x(x - 2)(x2 + 2x + 4)
x^4 + 125x = x(x^3 + 125) = x(x+5)(x^2-5x+25)
x^4 + 5x^3 + 4x^2 + 20x =
x(x^3+5x^2+4x+20) -
x(x^2(x+5)+4(x+5) = x(x^2+4)(x+5)
x^4 - x^3 -2x^2 + 2x =
x(x^3 -x^2 - 2x + 2) =
x(x^2(x - 1) - 2(x - 1)) =
x(x^2-1)(x-1)
x^4 - 8x = x(x^3 - 8) = x(x - 2)(x^2 +2x + 4)
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