Hi,
1) x 2 (x + 2)(x - 5) = 0 every parenthesis must be equal zero then find the answer-------> 0, -2, 5
3) (x 2 + 7)(x 2 + 5) = 0 the same
x 2 + 7 = 0 -----> x^2 = -7 root of both side --------> x = ±√7 i
x 2 + 5 = 0 ------> x^2 = -5 root of both side --------> x = ±√5 i
this equation has 4 complex roots
2) (x 2 + 9)(x 2 + 6) = 0
Exactly the same and complex answers will be x = ± 3i and ±√6 i
4) (x - 2)(x + 2)(x 2 + 4) = 0
x - 2 = 0 ------> x = 2 real
x + 2 = 0 ------> x = -2 real
x^2 + 4 = 0 -----> x^2 = -4 ----> x = ±2 i imaginary root
I hope it is useful.
Minoo