
Mark M. answered 10/29/20
Mathematics Teacher - NCLB Highly Qualified
The relationship is cubic
ax3 + bx2 + cx + d = y
Substituting 1, 2, 3, and 4
1) a + b + c + d = 1
2) 8a + 4b + 2c + d = 1
3) 27a + 9b + 3c + d = 4
4) 64a + 16a + 4c + d = 20
Subtracting 1 from 2
5) 7a + 3b + c = 3
Subtracting 2 from 3
6) 19a + 5b + c = 6
Subtracting 3 from 4
7) 37 a + 7b + c = 10
Subtracting 5 from 6
8) 12 a + 2b = 3
Subtracting 6 from 7
9) 18a + 2b = 4
Subtracting 8 from 9
6a = 1
a = 1/6
Now substitute a and determine b, c, and d.