Patrick B. answered 10/27/20
Math and computer tutor/teacher
Abs(m)=sqrt(m^2)
So the function can be written
Y = sqrt((x-3)^2)
Inverse goes like this:
X= sqrt((y-3)^2) <-- swaps
X^2 = (y-3)^2
Sqrt(x^2) = y-3
Abs(x)=y-3
Abs(x)+3=y
Technically the inverse is
Y= 3 +or- abs(x)
So no it is not a function unless the domain
Is restricted to either positive or negative