Chemistry help!

Question

A sample of a gas at room temperature occupies a volume of 32.0L at a pressure of 212torr . If the pressure changes to 1060torr , with no change in the temperature or moles of gas, what is the new volume, V2?

Answer 1

Hi Ayah,

 

We need to use the ideal gas law.

 

P * V = n * R * T.

 

This is a typical problem where the amount of gas (n) and the Temperature (T) are held constant.

 

So.

 

P * V (initial) = P * V (final)  or 

 

212 * 32.0 = 1060 * V2

 

Thus V2 = 212 * 32 / 1060 = 6.4 L

 

 

If you have any questions, send me a comment.

 

Sincerely,

Ralph K.