3 consecutive odd integers total to -27, what are they ?

Answer 1

We need to guarantee that the numbers we pick are odd numbers. To do that, why not first guarantee we start with an even number and then add 1 to it to get a guaranteed odd. To guarantee an even number, take any number and multiply it by 2. So, if "n" is any number, then "2n + 1" will be a guaranteed odd number. The next consecutive odd will be when I add 2 to that number so "2n + 3" and then the next consecutive odd will be "2n + 5".

So (2n + 1) + (2n + 3) + (2n + 5) = -27

6n + 9 = -27

6n = -36

n = -6

So, since the guaranteed odd number is 2n + 1, then the first odd number in the sequential series 2(-6) + 1 = -11. The next will be 2 more than that, so -9, the last will be -7

So: -11, -9, -7

Answer 2

assume the numbers are x, x+2, x+4,

so we have:

x+(x+2)+(x+4) = -27,

3x + 6 = -27,

3x = -33,

x = -11.

so the answer is -11, -9, -7.