find the slope intercept form parallel to y = 2 3 x – 10, x-intercept at

Question

i would like to know how to solve this problem

Answer 1

if y=(2/3)x-10, then the y-intercept =-10 and the slope = 2/3

set y=0 to find the x-intercept

0 = (2/3)x-10

(2/3)x = 10

x = (3/2)10 = 15

any line parallel to y= (2/3)x -10 will have the same slope = 2/3, but the y-intercept can be any real number

such as y=(2/3)x+10