If Jose has 15 dimes and nickels in his pocket, and they have a combined value of 120 cents, how many of each coin does he have?

Answer 1

D = number of dimes

N = number of nickels = 15 - D

10 *D = value of dimes

5* (15-D) = value of nickels

10 *D + 5* (15-D = 120

10 *D + 75 - 5*D = 120

5*D + 75 = 120

5*D = 45

D = 9

N = 15 - D = 15 - 9 = 6