How would you convert this equation to sum of cubes?

Question

b^2(a+b) - (ab(b-a) + a^2(b-a))

Answer 1

Just multiply the values outside the brackets and simplify:

b^2(a+b) - (ab(b-a) + a²(b-a))

ab² + b³ - ab² +a²b +a²b - a³

ab² + b³ - ab² +a²b +a²b - a³

b³ + 2a²b - a³

Bob

Answer 2

multiply everything out using the distributive property

ab^2+b^3-ab^2+a^2b-a^2b+a^3

b^3+a^3

a^3+b^3