Raymond B. answered 10/16/20
Tutor
5
(2)
Math, microeconomics or criminal justice
take the derivative and set it equal to zero, then solve for x
C'(x) = -60 + 0.4x = 0
0.4 x = 60
x = 60/0.4 = 600/4 = 150 trucks for minimum cost
C(150) = 13,000-60(150) + 0.2(150)^2 =13,000 -9000 + (1/5)(22500) = 13,000-9,000 + 4,500= 8,500 = minimum cost