
Patrick B. answered 10/15/20
Tutor
4.7
(31)
Math and computer tutor/teacher
f(x) = k(x+1)^2 (x-1)
5 = k(2+1)^2 (2-1)
5 = k(9)
5/9 = k
y = 5/9( x+1)^2 (x-1)
Luna S.
asked 10/14/20Real roots: −1 (with multiplicity 2), 1 and (2, f(2)) = (2, 5)
f(x) =
Patrick B. answered 10/15/20
Math and computer tutor/teacher
f(x) = k(x+1)^2 (x-1)
5 = k(2+1)^2 (2-1)
5 = k(9)
5/9 = k
y = 5/9( x+1)^2 (x-1)
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