write the equation of the line in slope intercept form that passes through the point (3,-5) and is parrallel to y=6x+1

Answer 1

For a line to be parallel it must have the same slope. So the slope of the new equation is 6.

The slope intercept form is y=mx+b. And we have a point (3,-5). Plug in what we know....

-5=6(3)+b

Solve for b (the y-intercept)

b= -23

Therefore.... y=6x-23