Carlos F.

asked • 10/10/20# Quantified Logic Translation

Using the given the symbolization key, translate the following sentences.

UD: | people |

Bx: | x is a baker. |

Jx: | x is a judge. |

Px: | x can make pâte à choux. |

Ux: | x lives under the sea. |

Sxy: | x is suspicious of y. |

m: | Mel |

n: | Nadiya |

p: | Paul |

- Some people are suspicious of everyone.
- Mel is suspicious of everyone who is suspicious of her.
- If a person is suspicious of themself, then everyone is suspicious of them.

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## 1 Expert Answer

1) There exists x in UD such that for very y in UD Sxy

2) For any x in UD, if SxM then SMx

3) For any x in UD, if Sxx then Syx for all y in UD

4) If there exists y in UD such that Syz for all z in UD

then there is t in UD such that Sty

Carlos F.

would 3 look somewhat like this: Ax(Sxx->AySyx) or could you tell me where im going wrong here
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10/10/20

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Carlos F.

There is someone who is suspicious of anyone who is suspicious of everyone. (forgot that one, but you don't have to answer it)10/10/20