If f(x)=4+sqrt(x) and g(x)=x^2+1 then f(g(x))=f(x^2+1)=4+sqrt(x^2+1)=h(x).
Similarly, if f(x)=4+x and g(x)=sqrt(x^2+1) then f(g(x))=f(sqrt(x^2+1))=4+sqrt(x^2+1)=h(x).
Michael H.
asked 10/09/20If h(x) = (f o g)(x) then list two possible ways to decompose the function h(x)= 4+ the square root of x^2+1
If f(x)=4+sqrt(x) and g(x)=x^2+1 then f(g(x))=f(x^2+1)=4+sqrt(x^2+1)=h(x).
Similarly, if f(x)=4+x and g(x)=sqrt(x^2+1) then f(g(x))=f(sqrt(x^2+1))=4+sqrt(x^2+1)=h(x).
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