So to begin this problem, we need to set a variable for each way to score. I'm going to use:
They scored 56 times which means the amount of touchdowns, field goals, and safety's = 56 or x+y+z = 56
A total of 295 points was scored. A touchdown is 7 points, a field goal is 3 and a safety is 2. This results in the equation 295 = 7x+3y+2z
As well as those two equations, we know there was 9 more touchdowns than field goals which means
x = y+9
Using substitution we can rewrite x+y+z = 56 as y+9+y+z = 56 which can also be rewritten as 2y+z = 47.
With a bit of algebraic rearrangement, we can get that z = 47-2y.
By plugging in the equations x = y+9, and z = 47-2y into the equation 295 = 7(y+9)+3y+2(47-2y)
Distributing then results in 295 = 7y+63+3y+94-4y, and by combining like terms it is found that 295 = 6y+157.
Subtract 157 from both sides and find that 138 = 6y. Divide by 6 to solve for y. I found that y = 23.
Plug the y value into the equation x = y+9 to find that x is 32.
Plug in both the x and y values into x+y+z = 56 to find that z = 1.
So the answer is that the Miami Dolphins had 32 touchdowns, 23 field goals, and 1 safety in the 2019 season.