The sum of four consecutive even integers is 124. What is the second largest integer?

Answer 1

Since the 4 integers are even and consecutive, each integer must be 2 larger than the one before it.

Take x to be the smallest of these integers.

That would make the sum of the 4 integers:

(x) + (x + 2) + (x + 4) + (x + 6) = 124

Which simplifies down to:

4x + 12 = 124

Subtract the 12:

4x = 112

Divide by 4:

x = 28

The smallest integer must be 28, however since you are looking for the second largest integer, you must add 4, as the second smallest would be 2 larger than the smallest, and the second largest would be 2 larger than that.

Therefore the second largest integer must be 28 + 4, which equals 32.