i need major help with my algebra 2

Question

questions are..

b) passes through the point (-6,-6) and is parallel to y=4/3x+2

and...

c) passes through the point (10,2) and is perpendicular to y=4x+6

Answer 1

If you are asking for the equation of the line that passes through the point (-6,-6) and is parallel to y=4/3x+2 then, the slope of that line would be equal to that of y=4/3x+2 (which is 4/3). Using the point-slope form of a line (y -y1) = m(x - x1) and plugging in the point (-6, -6), we get:

(y - -6) = 4/3(x - -6)

y + 6 = 4/3(x + 6)

This is finished unless you are required to put the equation into a particular format. If you need it in slope-intercept form then:

y + 6 = 4/3(x + 6)

y + 6 = 4/3x + 8

y = 4/3x + 2

If you need it in a different form, then you'll need to do the algebra to do so.

For question c), the perpendicular line has a slope that is the negative reciprocal of the slope of y=4x+6 which would be -1/4. Then just use the same point-slope form with the point (10, 2)

Answer 2

B) parallel lines have the same slope

M=4/3 x=y=-6

B= y - max

= -6 - (4/3)(-6)

= -6 + 8

= 2

So y = (4/3)x + 2

B) perpendicular lines have slopes whose product is -1

M= -1/4

X=10

Y=-2

B= y - mx

= -2- (-1/4)(10)

= -2 + 5/2

= 1/2

So y= (-1/4)x + 1/2