Hello, Kimani,
I set up a table to keep track. The three rounds are summarized with A = Acrobats, G = Grandmas, and I chose V for Ivan, because I looks too much like a "1." (Sorry, Ivan). The result (RSLT) is a tie for the first two and we need to predict the third, which I did on the "Predict" line in RED.
Since the first two events were ties, I set 4A = 5G and 1V = 2G. We now can substitute using these equivalencies in round 3 On side one, I know that 1V = 2G, so I gave Ivan some food and 2G in his place, for a total of 5G. On Side 2, I know that 4A = 5G, so I gave the clowns cupcakes and replaced them with 5G.
Those changes are reflected on the "Predict" line: 5G and 5G, so I predict a draw.
I hope this helps explain my logic,
Bob
Kim M.
Incorrect. 1 Ivan is equal to 2 grandmas and an acrobat, not just 2 grandmas. An acrobat is equal to 5/4 (or 1 1/4) grandmas. So, Ivan is equal to 2 grandmas and 1 1/4 grandmas, which is 3 1/4 grandmas. On the 3rd round, 3 1/4 grandmas (Ivan) plus 3 more grandmas equal 6 1/4 grandmas. That's greater than the 4 acrobats--who would equal 4(5/4 grandmas)---which is 5 grandmas. Signed--a new grandma who has far better things to do than play tug of war with acrobats and dogs....like babysit.10/28/22