Find three consecutive integers such that five times the middle integer is twice the sum of the other two integers.

Answer 1

x, x+1, x+2 are the 3 consecutive integers

5(x+1) = 2(x+x+2)

5x+5 = 4x + 4

x =-1

the 3 integers are -1, 0, and 1

5x0 = 2(-1+1)

0=0