The area of a rectangle is 44 m² in the length of the rectangle is 3 m less than twice the width find the dimensions of the rectangle

Answer 1

A=44 = LW = (2W-3)W = 2W^2 -3W

2W^2-3W -44 = 0

(2W-11)(W+4) = 0

2W-11 = 0

2W = 11

W = 11/2 = 5 1/2 meters

L=2W-3 = 11-3 = 8

8x11/2= 44

length = 8 m, width = 5 1/2 m