The area of a rectangle is 63 m² in the length of the rectangle is 11 m more than double the width find the dimensions of the rectangle

Answer 1

A=63 = LW = (11+2W)W = 11W +2W^2

2W^2 +11W -63 =0

(W+9)(2W-7)=0

2W=7

W=7/2 = 3 1/2 m

L=11+2W = 11+2(7/2) = 18 m

18 x 7/2 = 63 m^2

width = 3 1/2 meters, length = 18 meters

It's an 18x7/2 rectangle